Tuesday
July 29, 2014

Homework Help: Chemistry

Posted by Robert on Wednesday, November 25, 2009 at 1:50am.

Octane (C8H18) undergoes combustion according to the following thermochemical equation:
2 C8H18(l) + 25 O2(g) ---> 16 CO2(g) + 18 H2O(l) DHo = -11,200 kJ
Given : DHfo [CO2(g)] = -393.5 kJ/mol and DHfo[H2O(l)] = -285.8 kJ/mol.
Calculate the enthalpy of formation of one mole of liquid octane.

1) -6296 kJ
2. ) -120 kJ
3. ) -11,440 kJ
4. ) -5144 kJ
5. ) -240 kJ

I calculated 2 to be correct is it?

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