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January 25, 2015

January 25, 2015

Posted by **.** on Tuesday, November 24, 2009 at 8:37pm.

x-intercepts: 2,3

point: (4,2)

2. Write a quadratic function in standard form whose graph passes through the given points.

(1,-2),(-2,1),(3,6)

- Math -
**Reiny**, Tuesday, November 24, 2009 at 8:41pmfirst one is easy,

you know that x-2 and x-3 must be factors of the quadratic.

let the equation be

y = a(x-2)(x-3)

sub in (4,2) to solve for a, and you are done

the second takes a bit more work.

let the equation be

y = ax^2 + bx + c

now take each point and sub into that, giving you 3 equation in 3 unknowns.

first one:

-2 = a + b + c

take it from there.

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