Posted by . on Tuesday, November 24, 2009 at 8:37pm.
first one is easy,
you know that x-2 and x-3 must be factors of the quadratic.
let the equation be
y = a(x-2)(x-3)
sub in (4,2) to solve for a, and you are done
the second takes a bit more work.
let the equation be
y = ax^2 + bx + c
now take each point and sub into that, giving you 3 equation in 3 unknowns.
first one:
-2 = a + b + c
take it from there.
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