if a spinning amusement-park ride has an angular speed of 1.2 rad/s, what is the centripetal acceleration of a person standing 12m from the center of the ride?

a = R w^2

w is the angular velocity in rad/s (which you know). R = 12 m

if a spinning amusement park ride has an angular speed of 1.2 what is the centripetal acceleration of a person standing m from the center of the ride?

To find the centripetal acceleration of a person standing on a spinning ride, you can use the formula:

Centripetal acceleration (a) = (angular speed (ω))^2 × radius (r)

In this case, the given angular speed is 1.2 rad/s and the person's distance from the center (radius) is 12m.

To solve for the centripetal acceleration:

Step 1: Square the angular speed:
(1.2 rad/s)^2 = 1.44 rad^2/s^2

Step 2: Multiply the squared angular speed by the radius:
1.44 rad^2/s^2 × 12m = 17.28 m^2/s^2

Therefore, the centripetal acceleration of a person standing 12m from the center of the spinning ride is 17.28 m^2/s^2.