Posted by **julia** on Monday, November 23, 2009 at 10:39pm.

A 2.0 kg particle is moving along the x axis to the left with a velocity of v= -6.0 m/s. Suddenly, between times t =0 and t = 4.0 x a net force = 3t^2 – 12t is applied to the particle, where F is in N and t is in s. Calculate the velocity of the particle at t=4.0 s.

Is this formula right?

a= force/mass= (3t^2-12t)/4

v(4)=-12+a*t

now put t=4 into the equation

I get the acceleration as 0!!!

- physics -
**Ashley**, Tuesday, November 24, 2009 at 7:28am
A 2.0 kg particle is moving along the x axis to the left with a velocity of v= -6.0 m/s. Suddenly, between times t =0 and t = 4.0 x a net force = 3t^2 – 12t is applied to the particle, where F is in N and t is in s. Calculate the velocity of the particle at t=4.0 s.

Is this formula right?

a= force/mass= (3t^2-12t)/2

if so, I get 0

How do I find the velocity at 4s?

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