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April 20, 2014

April 20, 2014

Posted by **ggift** on Monday, November 23, 2009 at 9:28pm.

Solve by elimination method:

3r - 5s = 6

5r + 3s = 44

I thought that I could do vertical addition,when I do, I get 8r - 2s = 50...........but none of the variables are eliminated.

- Algebra -
**Anonymous**, Monday, November 23, 2009 at 10:23pmelimination method means to eliminate one of the variables.let us eliminate s.

3r - 5s = 6 ---I

5r + 3s = 44 --II

as a thumb rule multily eq I by 3 (coef. of s in eq II) and multiply eq II by 5 (coef. of s in eq II)

9r - 15s = 18 ---I

25r +15s = 220 --II

By vertical addition

34r=238

r=238/34=7

s=(3r-6)/5=(21-6)/5 =3

verification: sub stitute r and s in eq.1 we have

(3*7)-(5*3)=6 tallied hnece correct

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