Posted by ggift on .
please help me!!
Solve by elimination method:
3r  5s = 6
5r + 3s = 44
I thought that I could do vertical addition,when I do, I get 8r  2s = 50...........but none of the variables are eliminated.

Algebra 
Anonymous,
elimination method means to eliminate one of the variables.let us eliminate s.
3r  5s = 6 I
5r + 3s = 44 II
as a thumb rule multily eq I by 3 (coef. of s in eq II) and multiply eq II by 5 (coef. of s in eq II)
9r  15s = 18 I
25r +15s = 220 II
By vertical addition
34r=238
r=238/34=7
s=(3r6)/5=(216)/5 =3
verification: sub stitute r and s in eq.1 we have
(3*7)(5*3)=6 tallied hnece correct