Two vehicles with the same mass collide and lock together traveling 28 m/s at 37 degrees north of east after the collision. How fast was the car traveling that was heading north while the other vehicle was traveling east?

See:

http://www.jiskha.com/display.cgi?id=1258848458

To find the speed of the car heading north, we need to break down the 28 m/s velocity into its northward and eastward components.

The northward component can be found by multiplying the velocity (28 m/s) by the cosine of the angle (37 degrees):

Northward component = 28 m/s * cos(37 degrees)

Similarly, the eastward component can be found by multiplying the velocity (28 m/s) by the sine of the angle (37 degrees):

Eastward component = 28 m/s * sin(37 degrees)

Therefore, to find the speed of the car traveling north, we only need to know the northward component of the velocity.

Now let's calculate the northward component:

Northward component = 28 m/s * cos(37 degrees)
= 28 m/s * 0.7986
≈ 22.36 m/s

So, the speed of the car traveling north was approximately 22.36 m/s.