Two vehicles with the same mass collide and lock together traveling 28 m/s at 37 degrees north of east after the collision. How fast was the car traveling that was heading north while the other vehicle was traveling east?
See:
http://www.jiskha.com/display.cgi?id=1258848458
To find the speed of the car heading north, we need to break down the 28 m/s velocity into its northward and eastward components.
The northward component can be found by multiplying the velocity (28 m/s) by the cosine of the angle (37 degrees):
Northward component = 28 m/s * cos(37 degrees)
Similarly, the eastward component can be found by multiplying the velocity (28 m/s) by the sine of the angle (37 degrees):
Eastward component = 28 m/s * sin(37 degrees)
Therefore, to find the speed of the car traveling north, we only need to know the northward component of the velocity.
Now let's calculate the northward component:
Northward component = 28 m/s * cos(37 degrees)
= 28 m/s * 0.7986
≈ 22.36 m/s
So, the speed of the car traveling north was approximately 22.36 m/s.