Monday

March 30, 2015

March 30, 2015

Posted by **Anonymous** on Monday, November 23, 2009 at 9:41am.

An explanation of how to do this would be great, thanks.

- physics -
**drwls**, Monday, November 23, 2009 at 9:48amUse Kepler's third law. There is a particuarly simple form of it

P^2 = a^3

if you measure the period (P) in years and the distance (a) in astronomical units (a.u.). The earth's distance from the sun is 1 au. Mercury's is 5.79*10^7/1.50*10^8 = 0.386 au

You will find the formula at

http://www.windows.ucar.edu/tour/link=/the_universe/uts/kepler3.html&edu=high

and probably also in your textbook.

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