Thursday

April 17, 2014

April 17, 2014

Posted by **Anonymous** on Monday, November 23, 2009 at 9:41am.

An explanation of how to do this would be great, thanks.

- physics -
**drwls**, Monday, November 23, 2009 at 9:48amUse Kepler's third law. There is a particuarly simple form of it

P^2 = a^3

if you measure the period (P) in years and the distance (a) in astronomical units (a.u.). The earth's distance from the sun is 1 au. Mercury's is 5.79*10^7/1.50*10^8 = 0.386 au

You will find the formula at

http://www.windows.ucar.edu/tour/link=/the_universe/uts/kepler3.html&edu=high

and probably also in your textbook.

**Related Questions**

physics - At perihelion on Feb. 9, 1986, Halley’s comet was 8.79 × 107 km from ...

heeeeeeeeeeeelp physics vrey tough - Estimate the time difference between the ...

heeeeeeeeeeeelp physics - Estimate the time difference between the longest day ...

Phyics Toughest question on earth - Estimate the time difference between the ...

Physics - The average distance between Earth and the sun is 1.50e8 km. Calculate...

Chemistry - The velocity of light is 1.86 × 108 mi/hr. The distance of Mercury ...

Astronomy - The average distance between the Earth and the Sun is called the ...

physics - Find the ratio of the gravitational force on the Moon due to the Earth...

physics - Find the ratio of the gravitational force on the Moon due to the Earth...

math - Mercury is 5.79 x 10^7 km from the sun. Light travels at a speed of 3.0 x...