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September 30, 2014

September 30, 2014

Posted by **BELLA** on Sunday, November 22, 2009 at 7:42pm.

Can I get help with the equaiton?

The sum of the ages of Sonia, Collin, and Ana is 40. Sonia is twice as old as Ana. Ana is 6 years younger than Collin. How old are they? Write and solve an algebra equation.(may have decimals)

- ALGEBRA -
**MathMate**, Sunday, November 22, 2009 at 8:10pmIt's odd, most of the time, questions regarding ages are integer numbers. I agree with your answer, here's how you could have done it.

Let A,S, and C represent the age of each person.

The sum of the ages of Sonia, Collin, and Ana is 40, so

S+C+A=40......(1)

Sonia is twice as old as Ana, so

S=2A.......(2)

Ana is 6 years younger than Collin, so

C=A+6......(3)

Notice how S and C both have been expressed in terms of A.

Now substitute (2) and (3) in (1) to get

S+C+A=40

(2A)+(A+6)+A = 40

4A+6=40

4A=34

A=8.5

The rest is just substituting A=8.5 in equations (2) and (3).

Hope that helps.

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