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From a group of eight women and seven men, a committee of six is chosen randomly. Find the probability that three women and three men will be chosen.

  • Probability -

    number of ways to choose 3 women from 8 is C(8,3) or 56
    number of ways to choose 3 men from 7 is C(7,3) = 35
    number of ways to choose 6 people from 15 is C(15,6) = 5005

    so Prob(of stated situation) = 56(35)/5005 = 56/143

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