Saturday

December 20, 2014

December 20, 2014

Posted by **Lisa** on Sunday, November 22, 2009 at 5:36pm.

First I want to solve for y therefore I will let x be 0: 6y+5(0)=-18

6y=-18...I will now divide

y=-3 Therfore the first set to plot would be (0-3)

Now I solve for x, so I will let y be 0: 6(0)+5x=-18

5x=-18

x=-18/5

My second pair to plot is (-18/5,0)

the y intercept is (0,-3)

The second problem is the same concept as one, so I will not work it out as much herethe problem is 4x-12=3y

4(0)-12=3y

-12=3y

y=-4

(0,-4)

4x-12=3y

4x-12+12=3(0)-12

4x=-12

x=-3

(-3,0)

the y intercept is (0,-4)

The third problem is finding slope: x+4y=8

x(0)+4y=8

4y=8

y=2

(0,2)

x+4(0)=8

x=8

(8,0)

slope=1/4

Did I do these right?

- MATH...somewhat urgent -
**Reiny**, Sunday, November 22, 2009 at 5:46pmfirst one is correct

second one:

in 4x-12+12=3(0)-12

you added 12 on one side, but subtracted on the other.

should have been

4x-12+12=3(0)+12

4x = 12

x = 3, so x-intercept is (3,0)

last one:

change x+4y=8

to 4y = -x + 8

y = (-1/4)x + 2

comparing it to y = mx + b

we can see the slope is -1/4

your intercepts for the last one are correct.

- MATH...somewhat urgent -
**Lisa willsomeone look at this please**, Sunday, November 22, 2009 at 5:51pmThank you

- MATH...somewhat urgent -
**ashleigh**, Friday, February 5, 2010 at 3:23pm2x+4y+1=0

y= 2-1/3x

y-2x+2=0

3y-9x-1=0

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