MATH/ALGEBRA PLEASE
posted by Lisa on .
I am having a real issue with this one problem
the problem is : y=1/3x3
I am supposed to graph the problem and then find the y intercept.
First I substituted x with 12.
Y=1/3(12)3
s divided by 12 is 4, now I subtract 3from 4 and get 1
therefore, my first set reads(12,1)
I do the same operations for the second set, but this time I use 15, now I have my second set ( 15,2)
So mu ordered pairs are (12,1) and ( 15,2)
My y intercept is (0,3)
Did I do this right or is my answers wrong?

correct, good job

Thanks again!