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August 1, 2014

August 1, 2014

Posted by **Lisa** on Sunday, November 22, 2009 at 4:58pm.

the problem is : y=1/3x-3

I am supposed to graph the problem and then find the y intercept.

First I substituted x with 12.

Y=1/3(12)-3

s divided by 12 is 4, now I subtract 3from 4 and get 1

therefore, my first set reads(12,1)

I do the same operations for the second set, but this time I use 15, now I have my second set ( 15,2)

So mu ordered pairs are (12,1) and ( 15,2)

My y intercept is (0,-3)

Did I do this right or is my answers wrong?

- MATH/ALGEBRA PLEASE -
**Lisa willsomeone look at this please**, Sunday, November 22, 2009 at 5:38pmPlease help

- MATH/ALGEBRA PLEASE -
**Reiny**, Sunday, November 22, 2009 at 5:48pmcorrect, good job

- MATH/ALGEBRA PLEASE -
**Lisa willsomeone look at this please**, Sunday, November 22, 2009 at 5:51pmThanks again!

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