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December 17, 2014

December 17, 2014

Posted by **Jen** on Sunday, November 22, 2009 at 3:29pm.

A=6s^2, for s

A. A/6

B. SQRT A/6

C. -SQRT A/6

D. Not given

I believe the anser is B, but not 100% sure

- Algebra -
**Reiny**, Sunday, November 22, 2009 at 3:33pmalgebraically it would have been √(A/6),

but it said all variables are non-negative, so

√(A/6) , the A/6 must be all under the root sign.

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