What is the final concentration (M) of a solution prepared by diluting 50.0 mL of a 6.00 M KCl solution to a volume of 0.500 L?
E. none of these
My initial thought was to take the 6.00 M KCl/0.500 L, for an answer of 12. This baffles me that the only answer suitable would be E. None of the above--I think I did something wrong.
Word of advice!!! Never take a Chemistry class online!!!
Chemistry - DrBob222, Sunday, November 22, 2009 at 12:04am
You are diluting 6.00 M solution from 50 to 500 mL; therefore, the final concn is
6.00 x (50/500) = 0.600 M
There is another, more fundamental way of doing this.
1. How many moles do you have in the 6.00 M solution. moles = M x L = 6.00 x 0.05 L = 0.300 moles.
2. How many moles do you have in the diluted solution? Of course, 0.300 moles.
3. What is the concn? The definition, remember, is M = moles/L; therefore, M = 0.300 moles/0.5 L = 0.600 M.