Posted by christina on Saturday, November 21, 2009 at 10:32pm.
When the applied force doubles, the friction force will remain the same but the net force will go from zero to a new value equal to the friction force, M*g*Uk.
The acceleration rate will be
a = Fnet/m = m g *Uk /m = g Uk
Require that a*T = delta V = 1.0 m/s, and solve for T
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