Posted by **christina** on Saturday, November 21, 2009 at 10:32pm.

You push a 45 kg wooden box across a wooden floor at a constant speed of 1.0 m/s. The coefficient of kinetic friction is 0.15. Now you double the force on the box. How long would it take for the velocity of the crate to double to 2.0 m/s?

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**drwls**, Saturday, November 21, 2009 at 10:43pm
When the applied force doubles, the friction force will remain the same but the net force will go from zero to a new value equal to the friction force, M*g*Uk.

The acceleration rate will be

a = Fnet/m = m g *Uk /m = g Uk

Require that a*T = delta V = 1.0 m/s, and solve for T

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