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September 18, 2014

September 18, 2014

Posted by **Josh** on Saturday, November 21, 2009 at 7:30pm.

- physics -
**MathMate**, Saturday, November 21, 2009 at 11:09pmThe diagram looks like this:

UP ----> T1 <----1Kg---> T2 <----2Kg DOWN

The whole system is accelerating upwards at 2 m/s².

Start with the 2kg mass (m2).

The acceleration is due to T2 in excess of the weight due to the 2kg block, or T2-m2.g newtons.

Thus applying F=ma

(T2-m2g)=m2(a)

where a is the acceleration of 2 m/s²

Solve for T2

Now similarly consider the m1=1 kg mass.

Net force causing acceleration

=T1-m1g-T2.

Thus, again

T1-m1g-T2 = m1(a)

Solve for T1.

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