Posted by Josh on Saturday, November 21, 2009 at 7:30pm.
The diagram looks like this:
UP ----> T1 <----1Kg---> T2 <----2Kg DOWN
The whole system is accelerating upwards at 2 m/s².
Start with the 2kg mass (m2).
The acceleration is due to T2 in excess of the weight due to the 2kg block, or T2-m2.g newtons.
Thus applying F=ma
(T2-m2g)=m2(a)
where a is the acceleration of 2 m/s²
Solve for T2
Now similarly consider the m1=1 kg mass.
Net force causing acceleration
=T1-m1g-T2.
Thus, again
T1-m1g-T2 = m1(a)
Solve for T1.
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