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March 28, 2015

March 28, 2015

Posted by **Zach** on Saturday, November 21, 2009 at 5:18pm.

What are the length and width of the rectangle?

(Hint: Use the equations :

perimeter = times the sum of the length and the width

area = length times width)

- Math -
**RIFA**, Saturday, November 21, 2009 at 6:51pm94

- Math -
**Reiny**, Saturday, November 21, 2009 at 7:47pm2(l+w) = 34

l+w = 17 ,#1

lw = 60 , #2

from #1, w = 17-l

in #2

l(17-l) = 60

-l^2 + 17l - 60 = 0

l^2 - 17l + 60 = 0

(l-5)(l-12) = 0

so l=5 or l=12

if l=5 then w = 12

if l=12 then w = 5

The rectangle is 5 by 12

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