Posted by **jon** on Saturday, November 21, 2009 at 12:52pm.

The potential energy of a particle on the x-axis is given by U= 8xe ^-x ^2/19 where x is 1 meter and U is in Joules. Can you explain for me how to find the point on the x-axis for which the potential is a maximum or minimum and is this answer a point of maximum potential energy or minimum potential energy? Please show me how to figure this. Thanks

- physics -
**bobpursley**, Saturday, November 21, 2009 at 12:57pm
You use your calculus.

dU/dx, set to zero, solve for x

I don't know where the 19 goes, but take the derivative, set to zero

remember d/dx (uv)= vdu/dx + u dv/dx

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