Posted by Anna on Saturday, November 21, 2009 at 12:07pm.
I believe I answered this in an earlier post.
There are 9 possible values for the first digit and 9 for the second, and so on. So, there are 9^8 possible serial numbers, where no digits is a zero. Similarly, there are 8^8 possible values where no digit is a zero or a seven. So, the probability there is at least one seven is:
1- (8^8)/(9^8)
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