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September 20, 2014

September 20, 2014

Posted by **Lori** on Saturday, November 21, 2009 at 11:58am.

If the length of a rectangle is 3 feet longer than the width and

the diagonal I s 15 feet, then what are the length and width?

I do not understand how to solve this problem. Can someone help me?

Thanks.

- College Math II -
**Anonymous**, Sunday, November 22, 2009 at 8:18pm12x9

- College Math II -
**PsyDAG**, Monday, November 23, 2009 at 10:42amUse the Pythagorean theorem.

Hypotenuse^2 = sum of squares of other two sides

Let x = length, then width = x - 3

15^2 = x^2 + (x-3)^2

Does this help?

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