Posted by Amelia on Saturday, November 21, 2009 at 8:26am.
Int Udv= uv -int vdu
let dv=cosx v=sinx
U=e^bx du=be^bx
int e^bx*cosx=e^bx(sinx)-int(bsinx*e^bx
now, to handel the last term, let
dv=sinx v=-cosx
u=e^bx du=be^bx
int e^bx coxx=e^bx sinx-b[-e^bx cosx -int(-cosx be^bx)
int e^bx cosx=e^bx sinx+be^bx cos x+b^2e^bx cosx
gathering terms,
(1-b^2)int e^bx cosx=e^bx(sinx+bcosx)
and you can solve for your original integral underlined. CHECK MY WORK
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