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October 20, 2014

October 20, 2014

Posted by **Amelia** on Saturday, November 21, 2009 at 8:26am.

for integrate e^(bx) cos x

i get

= cos x e^bx/b - int -sin x e^bx/b

= cos x e^bx/b - -sin x e^bx/b^2 - int - cos x e^bx/b^2

this is where i get stuck please help

- Maths -
**bobpursley**, Saturday, November 21, 2009 at 9:05amInt Udv= uv -int vdu

let dv=cosx v=sinx

U=e^bx du=be^bx

int e^bx*cosx=e^bx(sinx)-int(bsinx*e^bx

now, to handel the last term, let

dv=sinx v=-cosx

u=e^bx du=be^bx

int e^bx coxx=e^bx sinx-b[-e^bx cosx -int(-cosx be^bx)

int e^bx cosx=e^bx sinx+be^bx cos x+b^2e^bx cosx

gathering terms,

(1-b^2)__int e^bx cosx__=e^bx(sinx+bcosx)

and you can solve for your original integral underlined. CHECK MY WORK

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