Posted by **Anonymous** on Friday, November 20, 2009 at 9:18pm.

Determine the solutions for:

(cos x)/(1 + sinx) + (1 + sinx)/(cosx) = 2

in the interval x is all real numbers, such that [-2 pi, 2pi]

- Advanced Functions -
**Reiny**, Friday, November 20, 2009 at 10:23pm
Multiply each term by cosx(1+sinx)

cos^2(x) + 1 + 2sinx + sin^2(x) = 2cosx(1+sinx)

2 + 2sinx = 2cosx(1+sinx) , recall sin^2(x) + cos^2(x) = 1

2(1 + sinx) = 2cosx(1+sinx)

now divide by 1+sinx to get

1 = cosx

for the given domain, x = -2pi,0,2pi

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