Posted by Anonymous on .
Determine the solutions for:
(cos x)/(1 + sinx) + (1 + sinx)/(cosx) = 2
in the interval x is all real numbers, such that [2 pi, 2pi]

Advanced Functions 
Reiny,
Multiply each term by cosx(1+sinx)
cos^2(x) + 1 + 2sinx + sin^2(x) = 2cosx(1+sinx)
2 + 2sinx = 2cosx(1+sinx) , recall sin^2(x) + cos^2(x) = 1
2(1 + sinx) = 2cosx(1+sinx)
now divide by 1+sinx to get
1 = cosx
for the given domain, x = 2pi,0,2pi