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September 16, 2014

September 16, 2014

Posted by **o** on Friday, November 20, 2009 at 8:58pm.

tanxcos^2x - tanx = 0

in the interval[-2pi, 2pi]

- math -
**bobpursley**, Friday, November 20, 2009 at 9:14pmtanx(cos^2x-1)=-tanxsin^2x

for that to be zero, then sinx is zero, tan x is zero. Where does that occur?

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