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January 28, 2015

January 28, 2015

Posted by **anonymous** on Friday, November 20, 2009 at 2:13pm.

- physics -
**MathMate**, Friday, November 20, 2009 at 6:56pmIn an elastic collision, both kinetic energy and momentum are conserved.

Let

m1=mass of red superball=1

m2=mass of blue superball=4

v11=initial velocity of red ball=5

v12=final velocity of red ball

v21=initial velocity of blue ball=0

v22=final velocity of blue ball

For conservation of energy,

(m1/2)v11² + (m2/2)v12² = (m1/2)v12² + (m2/2)v22².....(1)

For conservation of momentum,

(m1/2)v11 + (m2/2)v12 = (m1/2)v12 + (m2/2)v22 .......(2)

The only unknowns are v12 and v22. With the two equations, it is therefore possible to solve for the unknowns.

From (2), we express v12 in terms of the other unknown and the known constants, thus:

v12 = -(m2*v22-m2*v21-m1*v11)/m1

Substitute v12 into equation 1 will leave v22 as the only unknown.

Solving for v12 and v22, you should get

V12=-3 m/s, and v22=2 m/s.

Check that they satisfy the considerations of energy and momentum.

- physic-corr -
**MathMate**, Friday, November 20, 2009 at 7:01pmNote the following typographical corrections.

For conservation of energy,

(m1/2)v11² + (m2/2)**v21²**= (m1/2)v12² + (m2/2)v22².....(1)

For conservation of momentum,

m1 v11 + m2**v21**= m1 v12 + m2 v22 .......(2)

That is to say there is no need to divide the momentum by 2. Although this alone will not affect the final results.

- physics -
**Bob**, Sunday, June 23, 2013 at 3:55amtried solving it got different final results

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