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Posted by on Friday, November 20, 2009 at 10:20am.

A 71.4 kg satellite orbits the earth at a distance of 7.00E6 m from the center of the earth (a distance of 630 km above the earth's surface). How fast must the satellite be going to maintain its orbit if the free fall acceleration at this distance is 8.14 m/s^2?

  • physics - , Friday, November 20, 2009 at 10:22am

    8.14=v^2/r where r= 7e6 m

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