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AP Physics - Fluids

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A 6.0-cm diameter horizontal pipe gradually narrows to 4.0 cm. When water flows through this pipe at a certain rate, the gauge pressure in these two sections is 32 kPa and 24 kPa, respectively. What is the volume rate of flow?

I know to use Bernoulli's Equation and the Equation of Continuity, but I can't figure out how to solve for either velocity variable.

  • AP Physics - Fluids - ,

    P1 - P2 = (rho/2)(V2^2 - V1^2)= 8000 N/m^2 (Bernoulli equation)
    (rho is the fluid density)
    6^2*V1 = 4^2*V2, so V2 = (4/9)V1
    (from the continuity equation)

    Substitute (4/9)V1 for V2 in the first equation and solve for V1

    The volume flow rate is (pi/4)D^2*V1
    where D = 0.06 m

  • AP Physics - Fluids - ,


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