Posted by Jon on Thursday, November 19, 2009 at 7:53pm.
the initial KE of the block/arrow must be the same energy as the PE of the spring, so solve for speed from that.
The arrow hit the block, momentum was conserved
massarrow*speedarrow=(massarrow+block)speed above.
so use that speed to get the KE of the arrow.
The difference? It was an inelastic collision, what happened to the energy?
so what is the answer to b) and c)
Related Questions
Physics - A 0.500 kg block is sitting on a horizontal, frictionless surface. The...
physics - A physics student pulls a block of mass m = 23 kg up an incline at a ...
PHYSICS HELP - m1 = 2.7 kg block slides on a frictionless horizontal surface and...
PHYSICS HELP - m1 = 2.7 kg block slides on a frictionless horizontal surface and...
PHYSICS - m1 = 2.7 kg block slides on a frictionless horizontal surface and is ...
physics - m1 = 2.7 kg block slides on a frictionless horizontal surface and is ...
physics emergency - m1 = 2.7 kg block slides on a frictionless horizontal ...
physics - A moving 1.60 kg block collides with a horizontal spring whose spring ...
Physics - In 0.369 s, a 14.2-kg block is pulled through a distance of 3.60 m on ...
Physics - In 0.780 s, a 6.50-kg block is pulled through a distance of 3.85 m on ...
For Further Reading