Posted by **Anonymous** on Thursday, November 19, 2009 at 7:44pm.

An artillery shell is fired at an angle of 45.3◦ above the horizontal ground with an initial speed of 1710 m/s.

The acceleration of gravity is 9.8 m/s2 .

Find the total time of flight of the shell,

neglecting air resistance.

Answer in units of min.

- physics -
**bobpursley**, Thursday, November 19, 2009 at 7:51pm
Look at the vertical...that is what time it is in the air.

Hf=Hi+vivert*time- 1/2 g time^2

solve for time

vivert=1710*sin45.3 m/s

- physics -
**pedro**, Sunday, October 25, 2015 at 4:33pm
An artillery shell is fired at an angle of 67.1◦ above the horizontal ground with an initial speed of 1580 m/s.

The acceleration of gravity is 9.8 m/s2 .

Find the total time of flight of the shell, neglecting air resistance.

Answer in units of min.

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