Saturday
July 12, 2014

Homework Help: calulus

Posted by jackie on Thursday, November 19, 2009 at 7:35pm.

a particle is moving along the cure y=sqrt x. as the particle passes through the point (4,2), its x-coordinate increase at a rate of 3 cm/s. how fast is the distancefrom the particle to the origin changing at this instant?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

calculus - A particle is moving along the curve below. y = sqrt(x) As the ...
Calc - A particle is moving along the curve y= 4 sqrt{2 x + 2}. As the particle ...
Calculus HELP - A particle is moving along the curve y=5 sqrt (2x+6). As the ...
Calculus 1 - A particle is moving along the curve y= 4 \sqrt{3 x + 1}. As the ...
Calc - A particle is moving along the curve y= 3 \sqrt{3 x + 4}. As the particle...
Calculus - A particle is moving along the curve . As the particle passes through...
Calculus - A particle is moving along the curve . As the particle passes through...
Calculus - A particle is moving along the curve . As the particle passes through...
calculus - A particle is moving along the curve y=4((3x+1)^.5). As the particle ...
Maths - A particle is moving along the curve y=4sqrt(4x+1) . As the particle ...

Search
Members