Posted by jackie on .
a particle is moving along the cure y=sqrt x. as the particle passes through the point (4,2), its xcoordinate increase at a rate of 3 cm/s. how fast is the distancefrom the particle to the origin changing at this instant?

calulus 
bobpursley,
distance to origin=sqrt(x+ x^2)
d distance/dt= 1/(2sqrt(x+x^2)*(dx/dt+ 2xdx/dt)
you have x, dx/dt solve for ddistance/dt