e) Adjust the amplitude control of the function generator until the signal has a 6V peak-to-peak swing. The resultant form will have the following mathematical equation:
v = Vm sin2(pi)ft = 3sing2(pi)500t
f) The sinusoidal signal 3sin2(pi)500t has an effective value determined by:
Veff = 0.707(3V) = 2.121V
Connect the DMM directly across the function generator in the ac rms mode and adjust the oscilloscope output until Veff = 2.121V. Then connect the output of the function generator directly to the scope and note the total peak-to-peak. Is the waveform the same as that obtained in part (e)? Explain.
Can someone pls tell me whether they should be the same or dfferent? Thanks!
Physics - bobpursley, Thursday, November 19, 2009 at 2:53pm
They should be the same, if the input impedance of the Oscilloscope and DMM are very high.