Posted by **Sarah** on Thursday, November 19, 2009 at 3:08am.

A 0.260 kg block on a vertical spring with a spring constant of 5.00x10^3 N/m is pushed downward, compressing the spring 0.100 m. When released, the block leaves the spring and travels upward vertically. How high does it rise above the point of release?

- Physics -
**drwls**, Thursday, November 19, 2009 at 4:12am
It travels up until the gravitational energy gain, m g h, equals the potential energy of the compressed spring,

(1/2) k X^2.

Solve for h

- Physics -
**Anonymous**, Monday, March 17, 2014 at 12:13am
sdfsf

## Answer This Question

## Related Questions

- Physics - A 0.230 kg block on a vertical spring with spring constant of 4.25e3 N...
- physics - A 0.250 kg block on a vertical spring with a spring constant of 5.00 ...
- physics - A 0.250 kg block on a vertical spring with a spring constant of 5.00 ...
- physics - A 0.180 kg block on a vertical spring with spring constant of 4.00 &#...
- Physics - A 0.250 kg block on a vertical spring with a spring constant of 4.09...
- Physics - A 0.340 kg block on a vertical spring with a spring constant of 4.09...
- physics - Energy - A 0.280 kg block on a vertical spring with a spring constant ...
- Physics - A 0.250 kg block on a vertical spring with a spring constant of 4.09...
- PHYSICS - A 0.150 kg block is placed on a light vertical spring (k = 4.60 103 N/...
- Physics - A block of mass 0.229 kg is placed on top of a light, vertical spring ...

More Related Questions