Posted by Mare on Wednesday, November 18, 2009 at 11:07pm.
After the child stops pushing, the rotational acceleration is negative. it slows down.
Use the equation
alpha = L/I
where alpha is the angular DEceleration, I is the moment of inertia and L is the frictional torque.
To determine how long it takes to stop. you need to calculate how fast it is going when the pushing force stops. That is a somewhat harder problem, but uses the same equation. You need to calculate the angular acceleration rate while it is being pushed, and multiply that by the time (15 seconds).
Use the same L/I equation, but in this accvelerating case, the torque is the difference of the pushing and frictional torques.
Related Questions
Physics - A merry-go-round in the park has a radius of 1.8 m and a rotational ...
physics - A merry-go-round in the park has a radius of 1.8 m and a rotational ...
Physics Inertia : Merry-go-round - A playground merry-go-round of radius 1.96 m ...
physics - A 39.0kg child runs with a speed of 2.70m/s tangential to the rim of a...
Physics: merry-go-round question - A playground merry-go-round of radius 1.92 m ...
PHYSICS - A child pushes a merry-go-round with a force of 55.0 N at an angle ...
physics - A merry-go-round in a playground has a mass of 200 kg and radius of 1....
Physics - A merry-go-round with r = 4m and a perfect frictionless bearing is ...
Physics - In a playground, there is a small merry-go-round of radius 1.20 m and ...
Physics - A merry-go-round is rotating at 4.775 revs/min with a 45 kg child on ...
For Further Reading