Find the distance between the two points. Round an approximate result to the nearest hundredth.
(-1, -1) and (3, -7)
A) 7.21 B) 26 C) 6.93 D) 24
i don't know if i am doing something wrong but i keep getting the answer of 2
Yes, you are doing something wrong.
distance=sqrt( (x1-x2)^2 + (y1-y2)^2 )
Think of it like a right triangle.
The distance horizontally is 4 (from -1 to 3). The distance vertically is 6 (from -1 to -7).
You know the formula a^2 + b^2 = c^2 with c being the hypotenuse.
Therefore, 4^2 + 6^2 = c^2 and c is the distance between the points.
16 + 36 = c^2
52 = c^2
The square root of 52 is just more than 7 because 7^2 = 49. So your answer is A
What is the distance between P(–4, 3) and Q(6, 1)? Round to the nearest tenth.
To find the distance between two points in a coordinate plane, you can use the distance formula, which is based on the Pythagorean theorem.
The distance formula is given by:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
In this case, the points are (-1, -1) and (3, -7).
Let's substitute the values:
d = sqrt((3 - (-1))^2 + (-7 - (-1))^2)
Simplifying this, we have:
d = sqrt(4^2 + (-6)^2)
d = sqrt(16 + 36)
d = sqrt(52)
To get the approximate result rounded to the nearest hundredth, you can use a calculator or simplify manually:
sqrt(52) ≈ 7.211
Rounding to the nearest hundredth, the approximate result is 7.21.
Therefore, the correct answer is A) 7.21.