Posted by **Punkie** on Wednesday, November 18, 2009 at 5:32pm.

In a family with two children, what are the probabilities of the following outcomes, assuming that the birth of boys and girls is equally likely?

a. Both are boys.

b. The first is a girl and the second a boy.

c. Neither is a girl.

d. At least one is a girl.

I was wondering about the formula....

is a. P(probability) = 1/2(boy) + 1/2(boy)

P = 1/2 + 1/2

so P = 2/2

to me this doesn't seem right

- Math -
**bobpursley**, Wednesday, November 18, 2009 at 5:48pm
A) PR(B,B)=Pr(b)*Pr(b)=1/2*1/2

B) Pr(g)Pr(b)=1/2*1/2

C) you can get at least one girl these ways:

gb

bg

gg

Pr(at least one g)= 1/2*1/2*3

- Math -
**Punkie**, Wednesday, November 18, 2009 at 5:50pm
Thank you for answering my question.

Why do you multiply the probability of both boys, girl and boy, etc?

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