Posted by Izzy on .
Write the slope intercept form of an equation for the line that passes through (5,3) and is parallel to x+3y=6 . Please help me solve!!!!!!!!!!

Math 
bobpursley,
put the given equation into slope intercept form.
y=1/3 x +6
so the slope is 1/3
Now, your new line will be of the form
y=mx+b. To be parallel, it must have a slope of 1/3.
y=1/3 x + b
Now put the point on the line (5,3), and solve for b, and you have it, both m, and b. 
Math 
Izzy,
How would you solve for b?

Math 
bobpursley,
put y=3, x=5 into
y=1/3 x+ b
solve for b. 
Math 
Izzy,
ok thank you!! I got y=1/3x+4/5

Math 
bobpursley,
well that is not right at all.
y=1/3 x + b
b= y+1/3 x=3+5/3= 4 2/3 which is not 4/5
Did I make an error? 
Math 
Izzy,
I Have no idea...I put in the #s so that it was 3=1/3(5)+b

Math 
Izzy,
I see what I did wrong, forgot the negative sign.