Posted by **Izzy** on Wednesday, November 18, 2009 at 4:56pm.

Write the slope intercept form of an equation for the line that passes thru (5,3) and is parallel to x+3y=6 . Please help me solve!!!!!!!!!!

- Math -
**bobpursley**, Wednesday, November 18, 2009 at 5:01pm
put the given equation into slope intercept form.

y=-1/3 x +6

so the slope is -1/3

Now, your new line will be of the form

y=mx+b. To be parallel, it must have a slope of -1/3.

y=-1/3 x + b

Now put the point on the line (5,3), and solve for b, and you have it, both m, and b.

- Math -
**Izzy**, Wednesday, November 18, 2009 at 5:08pm
How would you solve for b?

- Math -
**bobpursley**, Wednesday, November 18, 2009 at 5:10pm
put y=3, x=5 into

y=-1/3 x+ b

solve for b.

- Math -
**Izzy**, Wednesday, November 18, 2009 at 5:18pm
ok thank you!! I got y=1/3x+4/5

- Math -
**bobpursley**, Wednesday, November 18, 2009 at 5:30pm
well that is not right at all.

y=-1/3 x + b

b= y+1/3 x=3+5/3= 4 2/3 which is not 4/5

Did I make an error?

- Math -
**Izzy**, Wednesday, November 18, 2009 at 5:58pm
I Have no idea...I put in the #s so that it was 3=1/3(5)+b

- Math -
**Izzy**, Wednesday, November 18, 2009 at 6:20pm
I see what I did wrong, forgot the negative sign.

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