Posted by Anonymous on Tuesday, November 17, 2009 at 9:08pm.
First, calculate the time T that it takes to fall Y = 0.51 m. That time will not be affected by the initial horizontal velocity.
Since Y = (1/2) g T^2,
T = sqrt(2Y/g) = 0.323 s
The initial velocity can be computed from the horizontal distance X that the mouse travels while falling, since
X = V T .
Solve for V
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