"Mr. Macho, my great dane, ate 125 hotdogs over a five-day period. Each day he atee seven more hot dogs than on the previous day. How many hot dogs did he eat on the first day?"
I got 55 hot dogs. Is this right??
Nope. How at that rate, he ate the 125 hotdogs in less than three days.
Day 1: 55
Day 2: 55 + 7 = 62
55 + 62 = 112
first day: x hotdogs
second day: x+7
third: x+14
fourth: x+21
fifth : x+28
x + x+7 + x+14 + x+21 + x+28 = 125
5x + 70 = 125
5x = 55
x = 11
so he ate 11, 18, 25, 32, 39
addd them up, it totals 125
well I thought tnis was right because the question stated that he ate 7 more than the previous day..
For example day 2 55+7 + 62
Day 3: 62 + 14 = 76 (7 more than day 2)
Day 4: 76 + 21 = 97 (7 more than day 3)
Day 5: 97 + 28 = 125(7more than day 4)
Thanks for everybodys help, I understand the math now.
i have th exact same problem!
To find out how many hot dogs Mr. Macho ate on the first day, we can use a little bit of algebra.
Let's say the number of hot dogs Mr. Macho ate on the first day is represented by x.
On the second day, Mr. Macho ate seven more hot dogs than on the first day, so he ate (x + 7) hot dogs.
On the third day, he ate seven more than the previous day, so he ate (x + 7 + 7) = (x + 14) hot dogs. Similarly, on the fourth day, he ate (x + 14 + 7) = (x + 21) hot dogs, and on the fifth day, he ate (x + 21 + 7) = (x + 28) hot dogs.
Now, we know that over the five-day period, he ate a total of 125 hot dogs. So, we can set up the equation:
x + (x + 7) + (x + 14) + (x + 21) + (x + 28) = 125
Simplifying the equation, we get:
5x + 70 = 125
Subtracting 70 from both sides, we get:
5x = 55
Dividing both sides by 5, we find:
x = 11
Therefore, Mr. Macho ate 11 hot dogs on the first day, not 55.
I see what you're thinking, but I believe you're wrong.
Each day he ate seven more hot dogs than on the previous day.
It seems to me the dog ate between 10 and 15 hotdogs the first day.