If a circle has the radius of 6 and it is at the orgin, what are seven points on the circle. I already have four and I need three more. So far I have, (6,0) (0,6) (0,-6) and (-6,0). What am I missing.
I also can't write any decimals for the points, but it can be expressed with a radicand or square root.
To find three more points on the circle with a radius of 6 centered at the origin, you can use the equation of a circle, which is given by:
(x - h)^2 + (y - k)^2 = r^2
Where (h, k) represents the center of the circle and r represents the radius. In this case, the center is the origin (0,0) and the radius is 6. Plugging in these values, the equation becomes:
(x - 0)^2 + (y - 0)^2 = 6^2
This simplifies to:
x^2 + y^2 = 36
Now, you can solve this equation to find the remaining three points on the circle.
1) To find the point with a positive x-coordinate and positive y-coordinate, you can assume x = 6. Plugging this into the equation, you get:
6^2 + y^2 = 36
36 + y^2 = 36
y^2 = 0
y = 0
Therefore, the point is (6, 0).
2) To find the point with a negative x-coordinate and negative y-coordinate, you can assume x = -6. Plugging this into the equation, you get:
(-6)^2 + y^2 = 36
36 + y^2 = 36
y^2 = 0
y = 0
Therefore, the point is (-6, 0).
3) Lastly, to find the point with a negative x-coordinate and positive y-coordinate, you can assume y = 6. Plugging this into the equation, you get:
x^2 + 6^2 = 36
x^2 + 36 = 36
x^2 = 0
x = 0
Therefore, the point is (0, 6).
In summary, the three missing points on the circle with a radius of 6 centered at the origin are (6, 0), (-6, 0), and (0, 6).