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Posted by on Tuesday, November 17, 2009 at 12:44am.

A block of wood with volume V floats in water with 0.68V submerged. In oil the block floats with 0.86V of its volume submerged.

What's the density of the wood?

  • Physics - , Tuesday, November 17, 2009 at 1:27am

    All you need to answer that is the amount submerged in water, and the density of water.

    According to Archimedes Principle:
    (Water density) * 0.68 V
    = (wood density)* V
    Cancel out the V and use the density of water
    1.00 g/cm^3 * 0.68 = wood density

  • Physics - , Tuesday, October 11, 2016 at 6:48am

    so you are telling that .68V = (Wood density)*V.....What if .40V(say) is submerged, then will it be .40V = (Wood density)*V ????......Ur theory is wrong.....

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