A block of wood with volume V floats in water with 0.68V submerged. In oil the block floats with 0.86V of its volume submerged.
What's the density of the wood?
Physics - drwls, Tuesday, November 17, 2009 at 1:27am
All you need to answer that is the amount submerged in water, and the density of water.
According to Archimedes Principle:
(Water density) * 0.68 V
= (wood density)* V
Cancel out the V and use the density of water
1.00 g/cm^3 * 0.68 = wood density
Physics - ryan, Tuesday, October 11, 2016 at 6:48am
so you are telling that .68V = (Wood density)*V.....What if .40V(say) is submerged, then will it be .40V = (Wood density)*V ????......Ur theory is wrong.....