How would I find out the area and perimeter of a square that is cut into two trianlges with a hypotenuse of 6squared2 and has two 45 degrees and one 90 degree angle?

Question

How would I find out the area and perimeter of a square that is cut into two trianlges with a hypotenuse of 6squared2 and has two 45 degrees and one 90 degree angle?

Answer 1

The hypotenuse squared = sum of the squares of the other two sides (Pothagorean theorum).

h^2 = s^2 + s^2

With the 45 degree angles, both sides will be the same length, therefore:

h^2 = 2s^2

You have h, so solve for s. The perimeter = 4s.

I'll let you do the calculations.