Public High School AP Physics B
posted by Corey on .
Ok I got a question
I'm confused by the compression ratio bit in this problem and don't know how to do it
If 3.00 m^3 of a gas initally at STP is placed under a pressure of 3.20 atm, the temperature of the gas rises to 38.0 degrees C. What is the volume?
I did this
p1V1/T1 = p2v2/T2
i then solved for T2 and got about 140 degrees K I think I did it wrong because of the compression ratio how do I do this problem THANKS!!!
Your equation is right but you want to solve for V2.
You should not be solving for T2. They told you what is is already. It is 38 C (315 K)
1 atm*3.00 m^2/273 K = 3.2 atm*V2/315 K
V = (315/273)*(1/3.2)*3.00 = 1.08 m^3