Posted by **Amber** on Monday, November 16, 2009 at 8:19am.

At noon a private plane left Austin for Los Angeles, 2100 km away, flying at 500km/h. One hour later a jet left Los Angeles for Austin at 700 km/h. At what time did they pass each other?

- Algebra -
**drwls**, Monday, November 16, 2009 at 10:44am
Let t be the time after the first jet leaves for LA, and x be the location of a plane, measured from LA.

2100 - x = 500 t

x = 700 (t -1) = 700 t - 700

Substitute 2100 - 500 t for x in the second equation and solve for t.

2100 - 500 t = 700 t - 700

2800 = 1200 t

t = 7/3 hours = 2 hours & 20 minutes

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