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a person pushes a 10kg mass at a constant speed across a u=0.150, 8.50m long floor at a constant speed
how much work does the person do? (125J)
how much work does friction do? ( -125J)

  • physics - ,

    The friction force is M g u = 10*9.81*.15 = 14.7 N

    Multiply Force x distance for work done. That would be 14.7 x 8.5 = 125 J

    Friction has the work done on it, and is therefore equal and opposite

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