Posted by Linds on .
A bungee jumper, whose mass is 87 kg, jumps from a tall platform. After reaching his lowest point, he continues to oscillate up and down, reaching the low point two more times in 8.5 s. Ignoring air resistance and assuming that the bungee cord is an ideal spring, determine its spring constant.
If he reaches the low point twice in 8,5 s, the period of oscillation is 4.25 s.
Use the formula for the Period to compute the value of the spring constant k
P = 2 pi sqrt (m/k)