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December 22, 2014

December 22, 2014

Posted by **Anna** on Sunday, November 15, 2009 at 10:48pm.

- Probability -
**economyst**, Monday, November 16, 2009 at 1:37pmWithout a zero, there must be 9^8 number of possible digits. Further there must be 8^8 possible digits that exclude both zero and 7. So, the probability at at least one seven appears is 1.-((8^8)/(9^8))

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