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you have 40 coins, quarters dimes and nickles and they equal $6.00. you have two more quarters then nickles. how many of each do you have

  • math -

    let the number of nickels be x (nickels, not nickles)
    then the number of quarters is x+2
    then the number of dimes is 40 - x - (x+2)
    or 38-2x

    5x + 25(x+2) + 10(38-2x) = 600


  • math -

    Let q = number of quarters
    let d = number of dimes
    let n = number of nickels.
    q + d + n = 40
    0.25q + 0.10d + 0.05n = 6.00
    q = n+2
    Solve for the three unknowns. Check my thinking.

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