Ok I do not know how to do this problem. I know that csc is simply sin^-1
sin (- pi/12) csc ( (37 pi)/12
ok now I know this also
sin (- pi /12 ) = - sin ( pi/12)
not really sure how that helps
I don't know were to go from here
( - sin (pi/12) )/(sin ( (25 pi)/12 ) )
Public High School Pre Calculus HH - bobpursley, Sunday, November 15, 2009 at 7:15pm
I thought I answered this.
Remember sin Theta=sin(theta+2PI)
and, remember that sin(-theta)=-sinTheta
and lastly, sin(theta)=-sin(theta+PI)
Now, to the task
sin(-PI/12)=-sin(PI/12)= + sin(PI/12+PI)
= sin(13PI/12+24pi/12)=sin 37PI/12
Now you have
READ - READ, Sunday, November 15, 2009 at 7:37pm
Why did you take the negative sign out?
I understand this
why are we adding pi to the denomenator
I udner stand that sin (theta) = sin (theta + 2pi)
= + sin(PI/12+PI)
I don't understand that
how did we get thirteen ontop?
I understood that
so you just rewrote 2pi in therms of a twelth (24pi)/12 makes sense
ok simplified it
ok so if you can explain the steps i don't understand that would be great thanks!!!!
Public High School Pre Calculus HH - bobpursley, Sunday, November 15, 2009 at 7:47pm
sin(PI/12 + PI) is not adding it to the denominator, If I wanted to add it to the denominator..
Sin(PI/12 + PI)=sin (PI/12 + 12PI/12)=
go back and reread what I did.
PLEASE READ - PLEASE READ, Sunday, November 15, 2009 at 8:13pm
ok then everything makes sense you just added pi to make it positive and then everything else makes perfect sense but allows you just to add pi to make it positive?
Public High School Pre Calculus HH - PLEASE READ, Sunday, November 15, 2009 at 8:15pm
will I do that on my calculator and get the same answer so I guess it's some kind of property of sin...???
PLEASE READ - PLEASE READ, Sunday, November 15, 2009 at 8:17pm
so then I can state this?
for sin (theta)
I can add pi to theta and still get the same answer??? this would appear to be true
does this also hold true for cosine and tangent?
READ READ READ - PLEASE READ, Sunday, November 15, 2009 at 8:21pm
sin - theta + pi = sin theta
cos - theta + pi = cos -theta
ok then I can just simply add pi to it to change it's sign (positive or negative) just like I could with anything without changing it's value????
so we can just simply add pi to theta because it dosen't change its value but it change it's sign which we can do because...
So What Did I do Wrong - So What Did I do Wrong, Sunday, November 15, 2009 at 8:28pm
I put this into my calculator and get negative one not positive one