Public High School Pre Calculus HH
posted by Public High School Pre Calculus HH on .
Ok I do not know how to do this problem. I know that csc is simply sin^-1
sin (- pi/12) csc ( (37 pi)/12
ok now I know this also
sin (- pi /12 ) = - sin ( pi/12)
not really sure how that helps
I don't know were to go from here
( - sin (pi/12) )/(sin ( (25 pi)/12 ) )
I thought I answered this.
Remember sin Theta=sin(theta+2PI)
and, remember that sin(-theta)=-sinTheta
and lastly, sin(theta)=-sin(theta+PI)
Now, to the task
sin(-PI/12)=-sin(PI/12)= + sin(PI/12+PI)
= sin(13PI/12+24pi/12)=sin 37PI/12
Now you have
Why did you take the negative sign out?
I understand this
why are we adding pi to the denomenator
I udner stand that sin (theta) = sin (theta + 2pi)
= + sin(PI/12+PI)
I don't understand that
how did we get thirteen ontop?
I understood that
so you just rewrote 2pi in therms of a twelth (24pi)/12 makes sense
ok simplified it
ok so if you can explain the steps i don't understand that would be great thanks!!!!
sin(PI/12 + PI) is not adding it to the denominator, If I wanted to add it to the denominator..
Sin(PI/12 + PI)=sin (PI/12 + 12PI/12)=
go back and reread what I did.
ok then everything makes sense you just added pi to make it positive and then everything else makes perfect sense but allows you just to add pi to make it positive?
will I do that on my calculator and get the same answer so I guess it's some kind of property of sin...???
so then I can state this?
for sin (theta)
I can add pi to theta and still get the same answer??? this would appear to be true
does this also hold true for cosine and tangent?
sin - theta + pi = sin theta
cos - theta + pi = cos -theta
ok then I can just simply add pi to it to change it's sign (positive or negative) just like I could with anything without changing it's value????
so we can just simply add pi to theta because it dosen't change its value but it change it's sign which we can do because...
I put this into my calculator and get negative one not positive one