Find the center and ardius of the circle
(x-1)2nd power+y2nd power=36
Square root it to make it a little easier to see first. x-1+y=6 or x+y=7. The center has to be some point with coordinates (x,y). A radius is half of the diameter across that runs through the center. Drawing a labled circle would be a good idea.
Your center is (1 or -1,0). Y^2-0 is still y^2.
To find the center and radius of a circle given its equation in the form (x - h)^2 + (y - k)^2 = r^2, we can compare it to the general equation of a circle: (x - a)^2 + (y - b)^2 = r^2.
Comparing the given equation (x - 1)^2 + y^2 = 36 to the general equation, we can determine that the center of the circle is (1, 0) and the radius is √36, which simplifies to 6.
Therefore, the center of the circle is (1, 0) and the radius is 6.