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math... precalculus

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how do i solve this equation?
log3x+log3(x-24)=4

  • math... precalculus - ,

    I will assume you mean log3 for all

    log3x+log3(x-24)=4

    log3 (x/(x-24)) = 4
    3^4 = x/(x-24)
    81 = x/(x-24)
    81x - 1944 = x
    x = 24.3

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