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December 22, 2014

December 22, 2014

Posted by **rimmel** on Sunday, November 15, 2009 at 1:52pm.

- calculus 2 -
**drwls**, Sunday, November 15, 2009 at 4:06pmI would estimate it using the first two terms of a McLaurin series expansion:

f(4.013) = f(4) + (4.013-4) f'(x)

= f(4) + 0.013 f'(4)

where f(4) = 2, and

f'(4) = 4f(4) + 2*4 = 16

So, f(4.013) = 2 + 0.013*16 = 2.208

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