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Posted by **THOMAS HARDY** on Sunday, November 15, 2009 at 7:58am.

2p-1,7 and 3P three consecutive terms of ARITHMETIC PROGRESSION

- MATH -
**tchrwill**, Sunday, November 15, 2009 at 9:53amWhat value of p are 2p-1, 7 and 3p three consecutive terms of an ARITHMETIC PROGRESSION?

Letting a = the common difference, we can write

1--(7 - a) = 2P - 1 and

2--(7 + a = 3p

Adding yields 14 = 5p - 1 from which p = 3 making the 3 terms 5, 7 and 9.

- MATHhanley -
**ty**, Tuesday, November 17, 2009 at 9:28pmfiger math for 2nd grade

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